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11x^2-46x+8=0
a = 11; b = -46; c = +8;
Δ = b2-4ac
Δ = -462-4·11·8
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-42}{2*11}=\frac{4}{22} =2/11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+42}{2*11}=\frac{88}{22} =4 $
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